How to get from Keilor Park Dr to Deakin University by bus, train and tram?
From Keilor Park Dr to Deakin University by bus, train and tram
To get from Keilor Park Dr to Deakin University in Burwood, you’ll need to take one bus line, one train line and one tram line: take the 903 bus from Keilor Park Dr station to Essendon Station/Mt Alexander Rd station. Next, you’ll have to switch to the CRAIGIEBURN train and finally take the 75 tram from Swanston St/Flinders St #5 station to Deakin University/Burwood Hwy #63 station. The total trip duration for this route is approximately 1 hr 40 min. The ride fare is A$5.30.
Step by Step
- 1Start from bus stationKeilor Park Dr
- 2Wait for bus903Mordialloc Sc
- 3Ride to bus stationEssendon Station/Mt Alexander RdID 5177114 min
- 4Walk to train stationEssendon Railway StationID vic:rail:ESD260 m • 4 min
- 5Wait for trainCRAIGIEBURNFlinders Street Via City Loop
- 6Ride to train stationFlinders Street Railway StationID vic:rail:FSS21 min
- 7Walk to tram stationSwanston St/Flinders St #5ID 18090150 m • 2 min
- 8Wait for tram75Vermont South
- 9Ride to tram stationDeakin University/Burwood Hwy #63ID 2110343 min
- 10Walk toDeakin UniversityHolland Avenue290 m • 4 min
From Keilor Park Dr to Deakin University by bus
Take one direct bus from Keilor Park Dr to Deakin University in Burwood: take the 903 bus from Keilor Park Dr station to Deakin University/Elgar Rd station. The total trip duration for this route is approximately 2 hr 6 min. The ride fare is A$5.30.
Step by Step
- 1Start from bus stationKeilor Park Dr
- 2Wait for bus903Mordialloc Sc
- 3Ride to bus stationDeakin University/Elgar RdID 6505118 min
- 4Walk toDeakin UniversityHolland Avenue620 m • 8 min
Public transport directions from Keilor Park Dr to Deakin University
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From Keilor Park Dr to Deakin University by bus
Take one direct bus from Keilor Park Dr to Deakin University in Burwood: take the 903 bus from Keilor Park Dr station to Deakin University/Elgar Rd station. The total trip duration for this route is approximately 2 hr 6 min. The ride fare is A$5.30.
Step by Step
- 1Start from bus stationKeilor Park Dr
- 2Wait for bus903Mordialloc Sc
- 3Ride to bus stationDeakin University/Elgar RdID 6505118 min
- 4Walk toDeakin UniversityHolland Avenue620 m • 8 min
Questions & Answers
What is the fastest way to get from Keilor Park Dr to Deakin University?
The fastest way takes 100 minutes, using Bus line 903, Train line CRAIGIEBURN, Tram line 75.
What is the alternative route to get from Keilor Park Dr to Deakin University?
The alternative route takes 126 minutes, using Bus line 903.
Is there a direct bus between Keilor Park Dr and Deakin University?
No, you’ll have to take one bus line, one train line and one tram line in total. The total travelling time is 1 hr 40 min.
Which bus line goes from Keilor Park Dr to Deakin University?
The 903 bus line goes from Mordialloc Sc station near Keilor Park Dr in Keilor East to Essendon Station/Mt Alexander Rd station. From there you’ll have to take one train line and one tram line till Essendon Station/Mt Alexander Rd station near Deakin University in Burwood.
How long does it take to travel from Keilor Park Dr to Deakin University by bus, train and tram?
The total travel time between Keilor Park Dr in Keilor East and Deakin University in Burwood by bus, train and tram is about 1 hr 40 min.
Where do I get on the bus near Keilor Park Dr to get to Deakin University?
Get on the 903 bus from the Mordialloc Sc stop near Keilor Park Dr in Keilor East.
Where do I get off the bus when travelling between Keilor Park Dr and Deakin University?
Get off the bus at the Essendon Station/Mt Alexander Rd station, which is closest to Deakin University in Burwood.
When is the first bus from Keilor Park Dr to Deakin University?
The first bus from Keilor Park Dr in Keilor East to Deakin University in Burwood is Mordialloc - Altona. It leaves the Keilor Park Dr stop at 19:10.
How much is the total bus, train and tram fare from Keilor Park Dr to Deakin University?
The ride from Keilor Park Dr to Deakin University costs A$5.30.
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