How to get from Lindau Ln & 26th Ave S to Shakopee, MN by bus?

From Lindau Ln & 26th Ave S to Shakopee, MN by bus

To get from Lindau Ln & 26th Ave S to Shakopee, MN in Shakopee, take the 495 bus from Mall Of America Transit Station Gate F station to Marschall Road Transit Station station. Next, take the 497 bus from Marschall Road Transit Station station to 1 Av at Fuller St NW Corner station. The total trip duration for this route is approximately 1 hr 24 min. The ride fare is $2.00. The bus schedule from Lindau Ln & 26th Ave S may change. We recommend you check the updated bus schedule to Shakopee, MN on the Moovit app.

84min$2.00
Walk to bus station
Bus - 495495
Bus - 497497
Walk to Shakopee, MN
Leaves from Mall Of America Transit Station Gate F

Step by Step

  • 1
    Walk to bus station
    Walk to bus station
    Mall Of America Transit Station Gate F
    ID 1844
    460 yd • 6 min
  • 2
    Bus - 495495
    Wait for bus
    495
    Marschall Road Transit Station
  • 3
    Ride to bus station
    Ride to bus station
    Marschall Road Transit Station
    ID 1723
    42 min
  • 4
    Bus - 497497
    Wait for bus
    497
    Downtown Shakopee
  • 5
    Ride to bus station
    Ride to bus station
    1 Av at Fuller St NW Corner
    ID 1728
    19 min
  • 6
    Walk to Shakopee, MN
    Walk to
    Shakopee, MN
    270 yd • 4 min
*Duration based on 8am traffic
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Public transit directions from Lindau Ln & 26th Ave S to Shakopee, MN

The distance between Lindau Ln & 26th Ave S and Shakopee, MN is approximately 25.51 mi, which can typically be travelled in 84 min. Moovit will show you the directions from Lindau Ln & 26th Ave S to Shakopee, MN by bus, so no matter how you choose to travel in Shakopee – you will always have plenty of easy options.

Bus schedule from Lindau Ln & 26th Ave S to Shakopee, MN

To check the bus schedule from Lindau Ln & 26th Ave S to Shakopee, MN using the Moovit app, first download and open the app on your smartphone. Enter your starting point (Lindau Ln & 26th Ave S) and destination (Shakopee, MN), then select the desired date and time of travel. Moovit will show all available bus routes, estimated travel times, and any required transfers. You can view detailed departure and arrival times for each bus, as well as real-time updates for delays or changes. Use this information to plan your trip and stay up to date with the latest bus schedules.

Related Routes

Questions & Answers

  • What is the fastest way to get from Lindau Ln & 26th Ave S to Shakopee, MN?

    The fastest way takes 84 minutes, using Bus line 495, Bus line 497.

  • Is there a direct bus between Lindau Ln & 26th Ave S and Shakopee, MN?

    No, you’ll have to take 2 bus lines in total. The total travelling time is 1 hr 24 min.

  • Which bus line goes from Lindau Ln & 26th Ave S to Shakopee, MN?

    The 495 bus line goes from Mall Of America Transit Station Gate F station near Lindau Ln & 26th Ave S in Bloomington to Marschall Road Transit Station. From there you’ll have to take one bus line till Marschall Road Transit Station near Shakopee, MN.

  • How long does it take to travel from Lindau Ln & 26th Ave S to Shakopee, MN by bus?

    The total travel time between Lindau Ln & 26th Ave S and Shakopee, MN by bus is about 1 hr 24 min.

  • Where do I get on the bus near Lindau Ln & 26th Ave S to get to Shakopee, MN?

    Get on the 495 bus from the Mall Of America Transit Station Gate F stop near Lindau Ln & 26th Ave S in Bloomington.

  • Where do I get off the bus when travelling between Lindau Ln & 26th Ave S and Shakopee, MN?

    Get off the bus at the Marschall Road Transit Station, which is closest to Shakopee, MN.

  • When is the last bus from Lindau Ln & 26th Ave S to Shakopee, MN?

    The last bus from Lindau Ln & 26th Ave S in Bloomington to Shakopee, MN in Shakopee is the Valleyfair-Mystic-Canterbury Park line. It leaves the Mall Of America Transit Station Gate F stop at 5:06 PM.

  • How much is the bus fare from Lindau Ln & 26th Ave S to Shakopee, MN?

    The ride from Lindau Ln & 26th Ave S to Shakopee, MN costs $2.00.

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