How to get from Kemper Rd 1135 to Sharonville by bus?
From Kemper Rd 1135 to Sharonville by bus
Take one direct bus from Kemper Rd 1135 to Sharonville in Sharonville: take the 67 bus from Kemper Rd 1135 station to Sharon Rd & Ohio Ave station. The total trip duration for this route is approximately 25 min. The ride fare is $2.00. The bus schedule from Kemper Rd 1135 may change. We recommend you check the updated bus schedule to Sharonville on the Moovit app.
Step by Step
- 1Start from bus stationKemper Rd 1135
- 2Wait for bus67Kemper Road To Fields Ertel Park & Ride
- 3Ride to bus stationSharon Rd & Ohio AveID 726325 min
Public transit directions from Kemper Rd 1135 to Sharonville
Bus schedule from Kemper Rd 1135 to Sharonville
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Questions & Answers
What is the fastest way to get from Kemper Rd 1135 to Sharonville?
The fastest way takes 25 minutes, using Bus line 67.
Is there a direct bus between Kemper Rd 1135 and Sharonville?
Yes, there’s a direct bus going from Kemper Rd 1135 in Forest Park to Sharonville in Sharonville in 25 min.
Which bus line goes from Kemper Rd 1135 to Sharonville?
The 67 bus line goes from Kemper Rd 1135 station near Kemper Rd 1135 in Forest Park to Sharon Rd & Ohio Ave station near Sharonville in Sharonville.
How long does it take to travel from Kemper Rd 1135 to Sharonville by bus?
The total travel time between Kemper Rd 1135 and Sharonville by bus is about 25 min.
Where do I get on the bus near Kemper Rd 1135 to get to Sharonville?
Get on the 67 bus from the Kemper Rd 1135 stop near Kemper Rd 1135 in Forest Park.
Where do I get off the bus when travelling between Kemper Rd 1135 and Sharonville?
Get off the bus at the Sharon Rd & Ohio Ave stop, which is closest to Sharonville.
When is the last bus from Kemper Rd 1135 to Sharonville?
The last bus from Kemper Rd 1135 in Forest Park to Sharonville in Sharonville is the Kemper Road line. It leaves the Kemper Rd 1135 stop at 5:35 PM.
How much is the bus fare from Kemper Rd 1135 to Sharonville?
The ride from Kemper Rd 1135 to Sharonville costs $2.00.
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