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How to get from Saticoy / De Soto to Ucla by bus?

From Saticoy / De Soto to Ucla by bus

To get from Saticoy / De Soto to Ucla in Westwood, you’ll need to take 3 bus lines: take the 244 bus from De Soto / Saticoy station to De Soto / Victory station. Next, you’ll have to switch to the CHATSWORTH - CANOGA PARK - NORTH HOLLYWOOD bus and finally take the 761 bus from Van Nuys / Oxnard station to Hilgard SB & Westholme FS station. The total trip duration for this route is approximately 1 hr 51 min. The ride fare is $1.75. The bus schedule from Saticoy / De Soto may change. We recommend you check the updated bus schedule to Ucla on the Moovit app.

111min$1.75
Walk to bus station
Bus - 244244
Bus - CHATSWORTH - CANOGA PARK - NORTH HOLLYWOOD
Bus - 761761
Walk to Ucla
Leaves from De Soto / Saticoy

Step by Step

  • 1
    Walk to bus station
    Walk to bus station
    De Soto / Saticoy
    50 yd • 1 min
  • 2
    Bus - 244244
    Wait for bus
    244
    Woodland Hills
  • 3
    Ride to bus station
    Ride to bus station
    De Soto / Victory
    6 min
  • 4
    Walk to bus station
    Walk to bus station
    De Soto Station
    ID 15453
    90 yd • 2 min
  • 5
    Bus - CHATSWORTH - CANOGA PARK - NORTH HOLLYWOOD
    Wait for bus
    CHATSWORTH - CANOGA PARK - NORTH HOLLYWOOD
    North Hollywood Station G Line
  • 6
    Ride to bus station
    Ride to bus station
    Oxnard / Van Nuys
    ID 4193
    31 min
  • 7
    Walk to bus station
    Walk to bus station
    Van Nuys / Oxnard
    ID 6177
    40 yd • 1 min
  • 8
    Bus - 761761
    Wait for bus
    761
    Expo / Sepulveda Station
  • 9
    Ride to bus station
    Ride to bus station
    Hilgard SB & Westholme FS
    51 min
  • 10
    Walk to Ucla
    Walk to
    Ucla
    Hilgard Ave, Los Angeles
    720 yd • 9 min
*Duration based on 8am traffic
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Public transit directions from Saticoy / De Soto to Ucla

The distance between Saticoy / De Soto, Westwood and Ucla, Westwood is approximately 23.6 mi, which can typically be travelled in 111 min. Moovit will show you the directions from Saticoy / De Soto to Ucla by bus, so no matter how you choose to travel in Westwood – you will always have plenty of easy options.

Bus schedule from Saticoy / De Soto to Ucla

To check the bus schedule from Saticoy / De Soto to Ucla using the Moovit app, first download and open the app on your smartphone. Enter your starting point (Saticoy / De Soto) and destination (Ucla), then select the desired date and time of travel. Moovit will show all available bus routes, estimated travel times, and any required transfers. You can view detailed departure and arrival times for each bus, as well as real-time updates for delays or changes. Use this information to plan your trip and stay up to date with the latest bus schedules.

Questions & Answers

  • What is the fastest way to get from Saticoy / De Soto to Ucla?

    The fastest way takes 111 minutes, using Bus line 244, Bus line CHATSWORTH - CANOGA PARK - NORTH HOLLYWOOD, Bus line 761.

  • Is there a direct bus between Saticoy / De Soto and Ucla?

    No, you’ll have to take 3 bus lines in total. The total travelling time is 1 hr 51 min.

  • Which bus line goes from Saticoy / De Soto to Ucla?

    The 244 bus line goes from De Soto / Saticoy station near Saticoy / De Soto in Canoga Park to De Soto / Victory station. From there you’ll have to take one bus line till De Soto / Victory station near Ucla in Westwood.

  • How long does it take to travel from Saticoy / De Soto to Ucla by bus?

    The total travel time between Saticoy / De Soto in Canoga Park and Ucla in Westwood by bus is about 1 hr 51 min.

  • Where do I get on the bus near Saticoy / De Soto to get to Ucla?

    Get on the 244 bus from the De Soto / Saticoy stop near Saticoy / De Soto in Canoga Park.

  • Where do I get off the bus when travelling between Saticoy / De Soto and Ucla?

    Get off the bus at the De Soto / Victory stop, which is closest to Ucla in Westwood.

  • How much is the bus fare from Saticoy / De Soto to Ucla?

    The ride from Saticoy / De Soto to Ucla costs $1.75.